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=-P^2+70P
We move all terms to the left:
-(-P^2+70P)=0
We get rid of parentheses
P^2-70P=0
a = 1; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·1·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*1}=\frac{0}{2} =0 $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*1}=\frac{140}{2} =70 $
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